In a certain number of two digits,the units digit exceeds the tens digit by 1.If the order of the digits is reversed the new number is 36 larger than the original number.Find the original number.
Answers
Number is 62.
Let say ‘x' is digit on one's place so 3x is digit on tens' place
So number is 10*3x+x=31x
Now if reverse the possition of digit new number is
10*x+3x=13x
As given new number is less by 36 from old number
31x-36=13x
18x=36
x=2
So number is 10*3*2+2=62.
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What is the greatest three digit number?
Why is the predecessor of a two digit number never a single digit number?
What is the product of the largest three digit number and the least three digit number?
What is the greatest ten digit number?
The one digit of a two digit number is 3 less than the tens digit the number is 19 more than five times the number of a digit what is the number?
Method 1: Let the number be 10x+y.
x=3y …(1)
10x+y-36 = 10y+x, or
9x=9y+36, or
x=y+4 …(2)
Equate (1) and (2),
3y = y+4, or
y = 2 and x = 6.
So the number is 62.
Method 2: Consider the numbers 31, 62, 93.
Subtract 36 from each of the above numbers : -5, 26, 44.
The number is 62 which gets reversed to 26 when you subtract 36 from it.
Answer : 62.
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Let number be ab = 10a + b
a = 3b
(10a + b) - (10b +a) = 36
Hence 9(a - b) = 36
a - b = 4
Substituting a = 3b into a - b = 4
2b = 4
b = 2 and a = 6
Check 62 - 26 = 36