Question

IN a certain of his 1/3 of the workers are women,1/2 of the women are married & 1/3 of the married women have children if 3/4 of the man are married & 2/3 of married man have children then what part of the workers are without children?

Answer 1

given, 1/3 = women, (1- 1/3=2/3)= men

1/3 = women

1/2 of women = married


so 1/3 *1/2 = 1/6 of whole office is married women

1/3 of married women have children
so 1/6 *1/3=1/18 of whole office is married
women with children

2/3 = men
3/4 of men = married
so 2/3 *3/4=1/2 people in office are married men
2/3 of married men have children
so 1/2*2/3=2/6 = 1/3 of whole office is married men with children

1/18 + 1/3 = married with children in office = 7/18 of office

so (1- 7/18=11/18) of office doesn't have children.

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Answer 2

Let the total number of workers be x. Then, 

 

Number of women = x/3 and number of men = x - x/3  = 2x/3

 

Number of women having children = x/18

 

Number of men having children = x/3

 

Number of workers having children = (x/18) + (x/3) = 7x/18

  

Therefore, workers having no children = x - 7x/18 = 11/18 of all workers...

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