In a certain oscillatory system,the amplitude of motion is 5m and the time period is 4s. The time taken by the particle for passing between points which are at distances of 4 m and 2 m from the centre and on the same side
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Amplitude A = 5
As the time period of the oscillatory system is 4 s, its frequency will be 1/4 Hz and the angular frequency will be ω = 2π/4
The displacement of the particular executing oscillatory motion system at any instant is given as x = A sin ωt
Let at time t1 & t2 the particular reaches position 2m and 4m from centre.
2 = 5 sin 2π/4 t1
4 = 5 sin 2π/4 t2
Calculate t1 and t2. The difference t = t2 - t1 is the time taken by the particular to pass through the given points.
As the time period of the oscillatory system is 4 s, its frequency will be 1/4 Hz and the angular frequency will be ω = 2π/4
The displacement of the particular executing oscillatory motion system at any instant is given as x = A sin ωt
Let at time t1 & t2 the particular reaches position 2m and 4m from centre.
2 = 5 sin 2π/4 t1
4 = 5 sin 2π/4 t2
Calculate t1 and t2. The difference t = t2 - t1 is the time taken by the particular to pass through the given points.
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