Question

In a certain process,400 Cal of heat are supplied to a system and at the same time 105j of mechanical work was done on the system.the increase in its internal energy is

Answer 1

Answer:

Given that the Heat energy (Q) supplied to the system = 400 J, Work done (W) on the system = 105 J and Increase in it's internal energy(U) = ?

From the 1st Law of thermodynamics we've;

U = Q - W

U = (400 J) -  (105 J)

U = 295 J

Explanation:

The increase in it's internal energy here is +ve in this case as the amount of heat supplied to it is more than the amount of work done on the system

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