In a certain process 400j of heat are supplied to a system and at the same time 150j of work are done by the system. What is the increase in the internal energy of the system
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Answer : 550J
Explanation :
dQ=du+dw (By sign convention)
dQ=+400Jquad (Heat absorbed is positive )
dw=−150J (heat given out is negative )
du=dQ−dw (Work done by the system is positive)
=400−(−150) (Work done on the system is negative )
=550J
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