Question

In a certain process 750J of heat is absorbed by a system while 150 cals of work is done on the system.What is the change in the internal energy for the process?

Answer 1

Answer:

According to the first law of thermodynamics,

ΔU= q + W (i)

Where, ΔU = change in internal energy for a process

q = heat

W = work

Given, q = + 701 J (Since heat is absorbed)

W = -394 J (Since work is done by the system)

Substituting the values in expression (i), we get

ΔU= 701 J + (-394 J) ΔU = 307 J

Hence, the change in internal energy for the given process is 307 J.

Answer 2

Answer:

In a certain process 750J of heat is absorbed by a system while 150 cals of work is done on the system.What is the change in the internal energy for the process?