Physics, asked by popstarastha3062, 10 months ago

In a certain region of space, electric field is along the z-direction throughout. The magnitude of electric field is, however, not constant but increases uniformly along the positive z-direction, at the rate of 105 NC−1 per metre. What are the force and torque experienced by a system having a total dipole moment equal to 10−7 Cm in the negative z-direction?

Answers

Answered by abhi178
6

a/c to question, electric field increases in positive z - direction from A to B [see figure ] . so,

electric field at B = electric field at A + electric field gradient × 2a.

or, E_B=E_A+\frac{dE}{dr}.2a

or, E_B-E_A=\frac{dE}{dr}.2a.....(1)

so, net force on electric dipole will be

F_{net}=F_B-F_A

= q(E_B-E_A)

from equation (1),

= q\frac{dE}{dr}.2a

= (q.2a)\frac{dE}{dr}

= p\frac{dE}{dr}

given, rate of electric field change , dE/dr = 10^5 N/Cm

and dipole moment, P = 10^-7 Cm

so, F = P dE/dr = (10^-7) × (10^5) = 10^-2 N

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