Question

in a certain school there were 132 examinees amd the ratio of successful to unsuccessful students was 9:2 . if 4 more students passed what would be the ratio of successful to unsuccessful students?

Answer 1

Sum of ratio=9+2= 11
The no of passed students=9*132/11=108
The no of failed students=2*132/11=24
If no of passed students is increased by 4,the no of failed students is decreased by 4, therefore the new ratio is 112:20 = 28:5

Answer 2

Answer:

Total Number of student = 132

The ratio of the pass : fail = 9 : 2

Number of student pass = 

911×132=108911×132=108

Number of student fail = 

211×132=24211×132=24

Now 4 student more passed.

∴ Number of student pass = 108 + 4 = 112 and,

Number of student fail = 24 - 4 = 20

New ratio of pass : fail = 112 : 20 = 28 : 5 mark as brainliest