Question

In a certain season, the Indian cricket team had a 40% success rate in the first 80 matches
it played. What is the minimum number of additional matches it must play so that it has a
60% success rate for the season ?
(A) 30
(B) 40
(C) 45
(D) 35​

Answer 1

40% of 80 matches is 32.

Let,Additional matches be 'x'

ATQ,

32+x/80+x= 60/100

By calculating, x=40.

So,Additional 40 matches is needed to win 60% matches.

Answer 2

Answer:  The answer is B 40

Step-by-step explanation:

Step 1: Given data

Success rate, s = 40% = 0.4

First matches played M = 80

New success rate required = 60% = 0.6

Step 2: Find number of initial wins

Initial success, s = No. of wins / First Matches played

s= $\frac{W}{80}$

0.4 X 80 = W

Therefore, number of wins W = 0.4 X 80 = 32

Step 3: Find extra matches to play so that success rate is 0.6

Let x be the extra matches to be played and win so that our new success rate is 0.6 ,

New success = 0.6 = 32+x/ 80+x

0.6(80 + x) = 32 + x

48 + 0.6x = 32 +x

16 = 0.4x

x = 16/0.4

x = 40

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