Question

In a certain semiconducting material the charge carries each have a charge 1.6x10 to the minus 19. C. How many are entering the semiconductor per second when the current 2.0nA?

Answer 1

Answer:

Answer below

Explanation:

I = Q/t

I = 2 A and t = 1 sec

Therefore,

Q = I*t

Q = 2*1 = 2 C

One electon consists of a charge of 1.6*10^-19 C. Then the number of electrons passing would be:

Q = n*e

n = Q/e

n = 2/(1.6*10^-19) = 1.25*10^19 electrons