In a certain test, the number of successful candidates was three times than that of unsuccessful candidates. If there had been 16 fewer candidates and if 6 more would have been unsuccessful, the numbers would have been as 2 to 1. Find the number of candidates.
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successful = S
unsuccessful= U
total= S+U
S= 3U ............(1) equation
16 Fewer means S+U-16
6 more unsuccessful means U+6
(S+U-16)/ U+6 = 2/1 ..........(2) equation
S-U = 28..........(3) equation
from equation 1&3
S=42, U=14
total= 56
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Answer:
Let's take the LCM of 8 and 6 to find the no of girls and boys in the school. i.e =24 then total no.of students in the school is = 24+24=48
Now, total students residing in the hostel={(24×1/8)girls + (24×5/6)boys}= 3 girls + 20 boys . We can say that , 4 boys don't residing in the hostel out of 24 boys and
4 boys don't residing in the hostel out of 48 students. i. e = 4/48= 1/12 boys are not residing in the hostel out of total students in the school
Ans. 1/12.
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