Question

In a certain time interval, the velocity of a car reduces from

72km/hr to 36 km/hr. If the car covers a distance of 150m during

this interval, find the negative acceleration​

Answer 1

Answer:

u=72km/hr=20m/s

v=36km/hr=10m/s

s=150m

v^2-u^2=2as

Therefore , a=v^2-u^2/2s

=10^2-20^2/2×150

=-1

Therefore negarive acceleration =-1

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