Question

In a certain time interval, the velocity of a car reduces from

72km/hr to 36 km/hr. If the car covers a distance of 150m during

this interval, find the negative acceleration​

Answer 1

Answer:

Explanation:

In this the initial velocity is 72 km/h and the final velocity is 36km/h. Distance covered is 150/1000km

Therefore using

v^2 -u^2 =2 aS

(36) ^2 -(72) ^2=2a×0.15

1296 - 5184=2a×0.15

-3888=a×0.3

a=-12960m/s^2