Question

In a certain time Rs. 1400 becomes Rs.
1848 at 8% p.a. simple interest. When
2,100 will become 2,604 at the same time,
the rate of interest is​

Answer 1

Answer:

T=4 yrs, R=6%

Explanation:

p=1400rs

A=1848

I=1848-1400=448

R=8%

T=100×I/PR

T=44800/1400×8

T=448/112

T=4 years

next p=2100

A=2604

I=2604-2100=504

T=4 years

R=?

R=100×I/PT

R=50400/2100×4

R=504/84

R=6%

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Answer 2

The answer is 4.8%

GIVEN

In a certain time Rs. 1400 becomes Rs. 1848 at 8% p.a. simple interest. When 2,100 will become 2,604 at the same time.

TO FIND

Rate of interest.

SOLUTION

The above problem can be simply solved as follows;

Principal amount = Rs 1400

Final Amount = Rs 1848

SI = Amount - Principal

= 1848 - 1400

= Rs 448

Let Time = T

Rate = 8%

Formula to calculate Simple interest

SI = PRT ÷ 100

448 = (1400 × 8 × T) ÷ 100

448 = 112T

T = 448/112 = 4 years

Now,

New Principal amount = Rs 2,100

Amount = Rs 2,604

SI = 2604 - 2100 = Rs 504

Let Rate = R

Time = 4 years

Putting the values in the formula

SI = (PRT) ÷ 100

504 =( 2100 × R × 5 ) ÷ 100

504 = 10,500R ÷ 100

504 = 105R

R = 504/105 = 4.8%

Hence, The answer is 4.8%

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