Math, asked by Abidkatalur862, 1 year ago

in a certain town 40% of the people have brown hair 25% have brown eyes and 10% have both brown hair and eyes what percent of the people in the town has neither brown hair nor brown eyes​

Answers

Answered by prk2002
2

Step-by-step explanation:

BH for brown hair and BE for brown eyes. Start from the intersection of BH and BE...

Attachments:
Answered by windyyork
4

45% of the people in the town has neither brown hair nor eyes.

Step-by-step explanation:

Since we have given that

Percentage of people have brown hair = 40%

Percentage of people have brown eyes = 25%

Percentage have brown hair and brown eyes = 10%

According to question, we get that

P(H)+P(E)-P(H\cap E)\\\\=40+25-10\\\\=65-10\\\\=55\%

So, Percentage of people has neither brown hair nor brown eyes is given by

100\%-55\%\\\\=45\%

Hence, 45% of the people in the town has neither brown hair nor eyes.

# learn more:

In a certain town 40% of the people have brown hair 25% have brown eyes and 10% have both brown hair and eyes what percent of the people in the town has neither brown hair nor brown eyes​.

https://brainly.in/question/12367089

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