Question

In a certain town, males and females form 50% of the population. It is known that 20% of the males and 5 % of the females are unemployed.A research student studying unemployment situations selects unemployed persons at random. What is the probability that the person selected is a) male and b)female?

Answer 1

Answer:

1/10 for (b)

(a) 2/5

Explanation:

The number of outcomes is here is 50% so, n(s)=50

males are 20%so,n(a)=20

females are 5%so,n(b)=5

(A) P(a)= n(a)/n(s)= 20/50= 2/5

(B) P(a)= n(b)/n(s)= 5/50= 1/10

20/50= 2 is for ×10

5 is for ×10

5/50 = 1 is for ×5

10 is for ×5

I hope you are satisfied

Answer 2

The probability of male is 0.80 and that of female is 0.20.

Given:

Population of male sand females = 50%

Males = 20%

Females = 5%

To Find:

Probability selection of male and female

Explanation:

According to the given question out of population of 50% the male percentage is 20%

then   $\frac{50}{100}$ × $\frac{20}{100}$

            = $\frac{10}{100}$

            =  0.10 ( are the unemployed males)

If Out of 50% only 5% is unemployed female then

          $\frac{50}{100}$ × $\frac{5}{100}$

          = $\frac{25}{1000}$

          = 0.025  ( are the unemployed females)

Let the female chosen be denoted by (F) and the male chosen denoted by (M).

Also let U be the number of unemployed person then

(a) Probability of choosing male is

     $P(\frac{M}{U})$ = $P(\frac{M\cap U}{P(U)})$

               =  $\frac{0.10}{0.125}$

               = 0.80

(b) Probability of choosing Female is

     $P(\frac{F}{U})$ =  $P(\frac{F\cap U}{P(U)})$

              = $\frac{0.025}{0.125}$

              = 0.20