Question

in a certain triangle one angle is twice as large as another and three times as large as the third find the measure of each angle​

Answer 1

$let \: one \: angle \: be \: 6x \\ so \: second \: angle \: is \: half \: of \: the \\ first \: as \: per \: the \: question \\ which \: is \: equal \: to \: 3x \\ third \: angle \: is \: \frac{1}{3} \: of \\ first \: which \: is \: equal \: to \: 2x \\ \\ so \: now \: 6x + 3x + 2x = 180 \\ = > 11x = 180 \\ = > x = \frac{180}{11} = 16.36 \\ \\ so \: 6x = 98.2 \\ 3x = 49.08 \\ 2x = 32.72$