In a certain unit, the radius of gyration
of a uniform disc about its central and
transverse axis is 2 5. . Its radius of
gyration about a tangent in its plane (in
the same unit) must be
(A) √5 (B) 2.5
(C) 2 √2.5(D) √12.5
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Given:
Radius of gyration of a uniform disc = 2.5
To Find:
Radius of gyration about tangent in its plane
Solution:
Moment of Inertia of disc about center of mass is I = mr²/2
Let a line parallel to x axis = d
Radius of a gyration = r
Thus, mR²/2 = mR²
= R² = R²/r
= R = R/√2
Now R/√2 = 2.5 (Given)
By theorum of perpendicular axis - Ix + Iy = Iz
where Ix, Iy and Iz are moment of inertia about x, y and z axis
Thus,
Ix = Iy = mR²/ 2 × 2 = mR²/4
mR²/4 + mR² = 5mR²/4
Let the tangent be = T
mT = 5mr/4
t = 5R²/2
Since r/√2 = 2.4
T = √5/√2 × 2.5
= √12.5
Answer: The radius of gyration is (D) √12.5
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