in a certain year, the population of a certain town was 12000. if the next year the population of males increases by 3% and that of the females by 7% and total population increases to 12800, then what was the ratio of population of males and females in that given year?
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let the male population be x
Female population be y.
the population of a certain town was 12000.
x + y = 12000
y = 12000- x...(1)
the population of males increases by 3% and that of the females by 7% and total population increases to 12800
net increase= 12800 - 12000 = 800
0.03x + 0.07y = 800
0.03x + 0.07(12000 -x) = 800
0.03x + 840 -0.07x = 800
-0.04x = 800 - 840
-0.04x = -40
0.04x = 40
x = 40/0.04 = 1000
substitute it in (1)
then y = 12000-1000 = 11000
The ratio of males and Female is
1000 : 11000 = 1:11
Female population be y.
the population of a certain town was 12000.
x + y = 12000
y = 12000- x...(1)
the population of males increases by 3% and that of the females by 7% and total population increases to 12800
net increase= 12800 - 12000 = 800
0.03x + 0.07y = 800
0.03x + 0.07(12000 -x) = 800
0.03x + 840 -0.07x = 800
-0.04x = 800 - 840
-0.04x = -40
0.04x = 40
x = 40/0.04 = 1000
substitute it in (1)
then y = 12000-1000 = 11000
The ratio of males and Female is
1000 : 11000 = 1:11
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