Question

In a chase in the time, a hare takes five
leaps a jackal takes four leaps If the
distance covered in four leaps of the
hare is equal to that covered in five
leaps of the jackal, find the ratio of their
speeds
Select one
a 25.16
b. 1.1
C. 4.5
d. 16:25​

Answer 1

Answer:

I think one option is missing

3 leaps of hare = 4 leaps of jackal ....(given)

i.e 1 leap of hare = 4/3 leaps of jackal.

for every 6 leaps hare,jackal takes 5 leaps.

6 leaps of hare = 6 * 4/3 leaps of jackal = 8 leaps ....1)

taking ratio

hare/jackal = 8/5

Answer 2

• The ratio of speed of hare and jackal is equal to 25 : 16 .

Given :-

• In same time, 5 leaps of hare = 4 leaps of jackal .
• Distance coverd in 4 leaps of hare = 5 leaps of jackal .

To Find :- The ratio of their speeds :-

A) 25 : 16

B) 1 : 1

C) 4 : 5

D) 16 : 25

Solution :-

given that,

→ 5 leaps of hare = 4 leaps of jackal

So,

→ Speed of hare : Speed of jackal = 5 leaps of hare : 4 leaps of jackal { Since time is constant , speed ∝ distance covered.} --------- Equation (1)

Now, we have also given that,

→ Distance coverd in 4 leaps of hare = Distance covered in 5 leaps of jackal .

→ Distance covered in 1 leap of hare = Distance covered in (5/4) leaps of jackal .

→ Distance covered in 5 leap of hare = Distance covered in (5×5/4) = (25/4) leaps of jackal -------- Equation (2)

therefore, Putting Equation (2) in Equation (1) we get,

→ Speed of hare : Speed of jackal = (25/4) leaps of jackal : 4 leaps of jackal

→ Speed of hare : Speed of jackal = (25/4) : 4

→ Speed of hare : Speed of jackal = (25/4)•4 : 4•4

→ Speed of hare : Speed of jackal = 25 : 16 (Ans.)

Hence, the ratio of their speed is equal to (A) 25 : 16 .

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