in a chemical equilibrium a + b give rise to C + D when 1 mole each of the two reactants are mixed 0.4 mole each of the products are formed the equilibrium constant is
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Given:
In a chemical equilibrium a+b=c+d when one mole each of the two reactant are mixed 0.4 moles each of the product are formed
To find:
Find equilibrium constant
Solution:
From given, we have,
a chemical equilibrium a+b=c+d
The equilibrium constant,
Kc = [c][d] / [a][b]
when one mole each of the two reactant are mixed 0.4 moles each of the product are formed
1 mole = x reactants + 0.4 products
1 mole - 0.4 products = x reactants
x reactants = 0.6 moles
therefore, when [c] = [d] = 0.4 moles
[a] = [b] = 0.6 moles
Therefore, the equilibrium constant,
Kc = (0.4 × 0.4)/(0.6 × 0.6)
Kc = 4/9
Therefore, the equilibrium constant Kc = 4/9
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