Chemistry, asked by YPawan, 1 year ago

in a chemical equilibrium a + b give rise to C + D when 1 mole each of the two reactants are mixed 0.4 mole each of the products are formed the equilibrium constant is

Answers

Answered by vasimjalegar27
107
hope it will help you
Attachments:
Answered by AditiHegde
7

Given:

In a chemical equilibrium a+b=c+d when one mole each of the two reactant are mixed 0.4 moles each of the product are formed

To find:

Find equilibrium constant

Solution:

From given, we have,

a chemical equilibrium a+b=c+d

The equilibrium constant,

Kc = [c][d] / [a][b]

when one mole each of the two reactant are mixed 0.4 moles each of the product are formed

1 mole = x reactants + 0.4 products

1 mole - 0.4 products = x reactants

x reactants = 0.6 moles

therefore, when [c] = [d] = 0.4 moles

[a] = [b] = 0.6 moles

Therefore, the equilibrium constant,

Kc = (0.4 × 0.4)/(0.6 × 0.6)

Kc = 4/9

Therefore, the equilibrium constant Kc = 4/9

Similar questions