In a chemical reaction 0•096gram of Boron combines with 0•144gram of oxygen to form a compound. Calculate the mass of compound form
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Answer:
Well, clealry the mass of the compound is 0.096⋅g+0.144⋅g=0.240⋅g...
Explanation:
And this mass was given to us in the terms of the question....all chemical reaction CONSERVE mass...
We could go further than this, and quote the empirical formula of the compound so formed...
Moles of boron=0.096⋅g10.81⋅g⋅mol=8.88×10−3⋅mol
Moles of oxygen=0.144⋅g16.00⋅g⋅mol=9.00×10−3⋅mol
...this specifies an empirical formula of near enuff to BO...
Answer:
Well, clealry the mass of the compound is 0.096⋅g+0.144⋅g=0.240⋅g...
Explanation:
And this mass was given to us in the terms of the question....all chemical reaction CONSERVE mass...
We could go further than this, and quote the empirical formula of the compound so formed...
Moles of boron=0.096⋅g10.81⋅g⋅mol=8.88×10−3⋅mol
Moles of oxygen=0.144⋅g16.00⋅g⋅mol=9.00×10−3⋅mol
...this specifies an empirical formula of near enuff to BO...
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