Question

In a chemical reaction N2 (g) 3H2 (g) give 2NH3 (g) if reaction starts with 1 mole of N2 and 4G of H2 then number of moles of NH3 produced will be –?

Answer 1

chemical reaction , N2 + 3H2 → 2NH3

here it is clear that 1 mole of N2 reacts with 3 mole of H2

or, 1 mole of N2 reacts with 6g of H2

but here given weight of H2 is only 4g. hence, H2 is limiting reagent. hence, number of mole of NH3 is found by using H2.

in reaction, 3 mole of H2 forms 2 mole of NH3

or, 6g of H2 forms 2 mole of NH3.

or, 4g of H2 forms 2/6 × 4 = 4/3 mole of NH3

hence, number of moles of NH3 = 4/3

Answer 2

Number of moles of $NH_3$ produced will be 1.33

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$      .....(1)

For hydrogen

Given mass of hydrogen= 4 g

Molar mass of hydrogen = 2 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen}=\frac{4g}2g/mol}=2mol$

The chemical equation for the reaction of nitrogen and hydrogen follows:

$N_2+3H_2\rightarrow 2NH_3$

By Stoichiometry of the reaction:

3 moles of hydrogen reacts with 1 mole of nitrogen

So, 2 moles of hydrogen gas will react with = $\frac{1}{3}\times 3=0.67mol$ of nitrogen

As, given amount of nitrogen is more than the required amount. So, it is considered as an excess reagent.

Thus hydrogen is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of hydrogen produces 2 moles of ammonia

So, 2 moles of hydrogen will produce = $\frac{2}{3}\times 2=1.33moles$ of ammonia

Thus number of moles of $NH_3$ produced will be 1.33

Learn more about stoichiometry

https://brainly.in/question/12620590

https://brainly.in/question/11902840