Question

In a chemical reaction of sodium carbonate (5.3g) and ethanoic acid (6 g) it forms (8.2g) sodium ethanoate, (2.2g) carbon dioxide and (0.9g) water.

Does this product formed follow the law of conservation of mass? ​

Answer 1

Answer:

In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water

sodium carbonate + ethanoic acid †’ sodium ethanoate + carbon dioxide + water

Mass of sodium carbonate=5.3g (given)

Mass of ethanoic acid=6g(given)

Mass of carbon dioxide=2.2g(given)

Mass of water=0.9g(given)

Mass of sodium ethanoate=8.2g(given)

Now total mass before reaction=(5.3g+6g)=11.3g

Now total mass after reaction=(8.2g+2.2g+0.9g)=11.3g

Total mass before reaction=total mass after reaction

Therefore the given observation is in agreement with law of conservation of mass.

n

Answer 2

Sodium carbonate $+$ ethanoic acid -------> Sodium ethanoate $+$ carbon dioxide $+$ water

(5.3g) (6g) (8.2g) (2.2g) (0.9g)

5.3 g $+$ 6g ------> 8.2 g $+$ 2.2g $+$ 0.9g

L.H.S $=$ R.H.S

11.3 g $=$ 11.3 g

It follows the law of conservation of mass.