Question

In a chemical reaction of sodium carbonate (5.3g) and ethanoic acid (6 g) it forms (8.2g) sodium ethanoate, (2.2g) carbon dioxide and (0.9g) water.

Does this product formed follow the law of conservation of mass? ​

Answer 1

Sodium carbonate $+$ ethanoic acid -------> Sodium ethanoate $+$ carbon dioxide ++ water

(5.3g) (6g) (8.2g) (2.2g) (0.9g)

5.3 g $+$ 6g ------> 8.2 g $+$ 2.2g $+$ 0.9g

L.H.S $=$ R.H.S

11.3 g $=$ 11.3 g

It follows the law of conservation of mass.

Answer 2

$\large{ \underline{ \bold{Answer}}}$

According to the question

$na_{2} co_{3} \: + \: ch_{3}cooh = = > co_{2} + h_{2}o \: + ch_{3}coona$

Mass of reactants = 5.3 + 6 = 11.3 gm

Mass of products = 2.2 + 0.9 + 8.2 = 11.3 gm

This shows, that during a chemical reaction, the mass of reactant = mass of the product.

Hence, it shows the law of conservation of mass.