Question

In a chemical reaction of sodium carbonate (5.3g) and ethanoic acid (6 g) it forms (8.2g) sodium ethanoate, (2.2g) carbon dioxide and (0.9g) water.

Does this product formed follow the law of conservation of mass? ​

Answer 1

${\huge{\underline{\underline{\mathfrak{\pink{A}\green{n}\blue{s}\red{w}\orange{e}\pink{r}}}}}}$

Sodium carbonate $+$ ethanoic acid -------> Sodium ethanoate $+$ carbon dioxide $+$ water

(5.3g) (6g) (8.2g) (2.2g) (0.9g)

5.3 g $+$ 6g ------> 8.2 g $+$ 2.2g $+$ 0.9g

L.H.S $=$ R.H.S

11.3 g $=$ 11.3 g

$\purple{\bold{It \:follows\: the \:law \:of \:conservation\: of\: mass}}$

Answer 2

$solution \\ \\ sodium \: carbon \: + \: ethanoic \: acid \: \: = \\ \: sodium \: ethanote \: + \: carbon \: dioxide \: + \\ \: water \\ \\ then \\ \\ 5.3 + 6 = 8.2 + 2.2 + 0.9 \\ \\ 11.3 = 11.3 \\ \\ hence \: this \: follows \: law \: of \: conversation \\ \: of \: masses$