Question

in a chemistry lab the room temperature is required to be lowered form 80 degree Celsius at the rate of of 4 degree Celsius every hour what will be the room temperature after 8 hours.​

Answer 1

Answer:

room temperature=80°C

cooling rate =. 5°C per hour

so room temperature after 10 hrs is. 30°C

Answer 2

Hope it helps you

Sol i)

• Quantity of water= 5 litre
• Vidya consumed= 2/5 ×5 l
• Simplify the fraction and the answer we get is - 2 litre

Sol ii)

• Remaining water= 1-2/5
• = 5-2/5
• =3/5
• Total quantity of water pratap drink =
• 3/5