In a Chemistry lab, there are three solutions, X, Y, Z, of an acid, of concentrations 30%, 40% and p% respectively. If 200 ml of X when mixed with V ml of Z, produces a solution of 60% concentration, and 250 ml of Y when mixed with V ml of Z, produces a solution of 62% concentration, find the value of p.
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If 100 ml of A when mixed with V ml of C, produces a solution of 60% concentration and 100 ml of B when mixed with V ml of C, produces a .
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Answer:
84
Step-by-step explanation:
x=30% y=40% z=p%
(200+v) (250+v)
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60% 62%
we will make 2 eqn
30x200+pv=60(200+v) ----(i)
40x250+pv=62(250+v) ----(ii)
on solving these two we get value of v is 250.
lets put v value in eqn 1
we get p=84%
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