In a chemistry lab two beakers A and B contains 36% and 40% of spirit respectively. If two liters from A is mixed with 4 liters of B. The ratio of sprit and water in the resulting mixture is:
Answers
If 2 litres from beaker A and 4 litres from beaker B are mixed together then the ratio of spirit and water in the resulting mixture is 29:46.
Step-by-step explanation:
Step 1:
Beaker A:
Initial amount of spirit = 36% = 36/100 = 9/25
Initial amount of water = 100 – 36 = 64% = 64/100 = 16/25
2 litres from beaker A are to be mixed:
So,
2 litres of spirit from A = 2 * (9/25) = 18/25 ….. (i)
2 litres of water from A = 2 * (16/25) = 32/25 …… (ii)
Step 2:
Beaker B:
Initial amount of spirit = 40% = 40/100 = 2/5
Initial amount of water = 100 – 40 = 60% = 60/100 = 3/5
4 litres from beaker B are to be mixed:
So,
4 litres of spirit from B = 4 * (2/5) = 8/5 ….. (iii)
4 litres of water from B = 4 * (3/5) = 12/5 …… (iv)
Step 3:
Adding (i) & (iii), we get
The amount of spirit from the mixture of beaker A & B = 18/25 + 8/5 = [18 + 40]/25 = 58/25 ….. (v)
And,
Adding (ii) & (iv), we get
The amount of water from the mixture of beaker A & B = 32/25 + 12/5 = [32 + 60]/25 = 92/25 ….. (vi)
Thus, from (v) & (vi), we get
The ratio of the spirit and water in the resulting mixture will be,
= 58/25 : 92/25
= 58 : 92
= 29 : 46
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