Question

In a children-park an inclined plane is constructed with an angle of incline 45° in the middle part (figure 6−E1). Find the acceleration of boy sliding on it if the friction coefficient between the cloth of the boy and the incline is 0.6 and g = 19 m/s2.
Figure

Answer 1

Explanation:

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Answer 2

The acceleration of boy sliding on it if the friction coefficient between the cloth of the boy and the incline is 0.6 and g = 19 m/s2. The acceleration is $22 \mathrm{m} / \mathrm{s}^{2}.$

Explanation:

Let the body mass of boy be denoted as m.

It is seen from the above figure:- $-m g \cos 45^{\circ}+R=0$

$R=m g \cos 45^{\circ}=m g^{2}$

On the boy, the acting net force when making him slide down = $n g \sin 45^{\circ}-\mu R$

$=m \times 10 \times 12 \times 12-0.6 \times m \times 10$

The acceleration of the boy = ForceMass $=22 m / s^{2}$