Question

In A china dish, Mixture of Iron and sulphur is taken and in china dish B, mixture of iron and 1 sulphur is heated. Components present in china dish A and B is treated with dilute hydrochloric acid. Identify the gases evolved in A and B.

Answer 1

Answer:

if iam correct it would be sodium hydroxide

Answer 2

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When iron mixed with sulphur and heated then it forms Ferrous sulphide (A) which on treatment with dilute HCl produces Ferrous chloride and Hydrogen sulphide gas. FeS + HCl →FeCl₂ + H₂S↑ If the mixture is not heated (B) remains as mixture (Fe + S) if it treated with dilute HCl then it produces Hydrogen gas along with Ferrous chloride . Since only iron reacts (Slowly) with HCl. (Fe + S) +2 HCl → FeCl₂ + H₂↑