Math, asked by Anonymous, 1 month ago

In a cinema hall, 300 tickets were sold for a
total of 32,000. If the tickets were of two
denominations of 80 and 120, how many
of each were sold?​

Answers

Answered by pushpapaveen
4

Answer:

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Answered by prince748856
23

Answer:

given that total tickets were sold = 300 of rate =32000

let be no of rs 80 tickets=x

then rs 120 tickets =(300 - x)

total cost of rs 80 tickets =80 * x =80x

total cost of rs 120 tickets = 120 * (300 - x) = 36000 -120x

total cost of both tickets = total cost of rs 80 tickets + total cost of rs 120 tickets = 32000

= 80x + 36000 - 120x = 32000 = -40x + 36000 = 32000

= 36000 - 32000 = 40x

=. 4000 = 40x

= x = 4000/40

=. x= 100

no of rs 80 tickets sold= x =100 tickets

no of rs 120 tickets sold = (300 - x) =(300 - 100) = 200 tickets ✔️

Step-by-step explanation:

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