Math, asked by sunil5699, 10 months ago


. In a cinema hall, 300 tickets were
total sale of the tickets was 1250
tickets were of two denominations of
and 35.00, how many of each denominati
were sold?

Answers

Answered by drishtirawat2005
4

Answer:

Hiii

Step-by-step explanation:

Sk7066Ambitious

Let the number of Rs 2.50 tickets be x and 5.00 tickets be y.

As per the question, x+y = 300 (eq.1)

Also, 2.5x + 5.0x = 1250

         2.5 ( x+2y)  = 1250

                 x+ 2y  = 1250/2.5

                 x+ 2y  = 500  (eq.2)

(eq 2) - (eq 1)

x+2y - x-y = 500-300

              y = 200

Substitute y in eq 1

x+200 = 300

x         = 300-200

       x  = 100

Therefore, there are 100 Rs 2.5 tickets and 200 Rs 5.00 tickets.

Hope it helps you...

Answered by Vraddhi
0

Step-by-step explanation:

No. of tickets of rs.2.50= x

No. of tickets of rs.5=y

A.T.Q. x+y =300 ....(1)

also,2.5x+5.0y=1250

2.5(x+2y)=1250

x+2y = 500 ...(2)

Now, eq.(1) -(2)

x+2y-x-y=500-300

y=20

substitution the value of y in eq (1),

x+200=300

x=100...

Therefore,the no. of tickets of rs.2.50 and rs.5.00 is 100 and 200 respectively.

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