. In a cinema hall, 300 tickets were
total sale of the tickets was 1250
tickets were of two denominations of
and 35.00, how many of each denominati
were sold?
Answers
Answer:
Hiii
Step-by-step explanation:
Sk7066Ambitious
Let the number of Rs 2.50 tickets be x and 5.00 tickets be y.
As per the question, x+y = 300 (eq.1)
Also, 2.5x + 5.0x = 1250
2.5 ( x+2y) = 1250
x+ 2y = 1250/2.5
x+ 2y = 500 (eq.2)
(eq 2) - (eq 1)
x+2y - x-y = 500-300
y = 200
Substitute y in eq 1
x+200 = 300
x = 300-200
x = 100
Therefore, there are 100 Rs 2.5 tickets and 200 Rs 5.00 tickets.
Hope it helps you...
Step-by-step explanation:
No. of tickets of rs.2.50= x
No. of tickets of rs.5=y
A.T.Q. x+y =300 ....(1)
also,2.5x+5.0y=1250
2.5(x+2y)=1250
x+2y = 500 ...(2)
Now, eq.(1) -(2)
x+2y-x-y=500-300
y=20
substitution the value of y in eq (1),
x+200=300
x=100...
Therefore,the no. of tickets of rs.2.50 and rs.5.00 is 100 and 200 respectively.