Question

In a circle AB and CD are two parallel chords. AB= 40 cm, CD= 30 cm and the diameter of circle is 50 cm, what is

the distance between the chords if they are on either side of the centre.?​

Answer 1

Answer:

Given OP⊥AB and OQ⊥CD

CQ = QD = 3 cm

AP = BP = 4cm

In △OPA

OP

2

=OA

2

–AP

2

=r

2

–4

2

=25–16=9

⟹OP=3

In △OCQ

OQ

2

=

r

2

–3

2

=4

PQ=OP+OQ=4+3=7cm