In a circle, AB is the
diameter of the circle DCll AB and
angle CAB= 29 degreefind angle DAC
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GIVEN :-
AB is a Diameter.
DC || AB
∠CAB = 29°
TO FIND :-
∠ADC = ?
SOLUTION :-
=> ∠ADB = 90°
∠CDB =∠CAB (Angle by Same Chord BC)
∠CDB = 25°.
∠ADC = ∠ADB + ∠CDB
=> ∠ADC = 90° + 25°
=> ∠ADC = 115°
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