Question

In a circle, chord AB is twice the
length of chord CD. OM is
perpendicular to CD and ON is
perpendicular to AB. Which of the
following is true?
O OM = ON
OM > ON
OM<ON
OM=1/2ON​

Answer 1

Answer:

In a circle, chord AB is twice the

length of chord CD. OM is

perpendicular to CD and ON is

perpendicular to AB. Which of the

following is true?

O OM = ON

OM > ON

OM<ON$x^{2} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \neq$

Answer 2

M = 1/2 on

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