Math, asked by kurmitrishanku, 10 months ago

in a circle chord ab of length 6cm is at a distance of 4 cm from the centre O. the length of another chord CD.which is also 4 cm away from the centre is?

Answers

Answered by mirazmuhammed22
0

Answer:

6 cm

Step-by-step explanation:

By pythagoras theorem:-

(h)²=(4)²+(6/2)²=(4)²+(3)²=16+9

h=√25

h=5 cm

radius of the circle =5 cm

now, again

by pythagoras theorem,

(radius)²=(4)²+(cd/2)²

(5)²=(4)²+(cd)²/4

25-16=(cd)²/4

9×4=(cd)²

CD=√36

CD=6 cm

Answered by Raghav1330
0

Given:

Length of chord AB = 6cm

The distance of AB from center O is 4cm

The distance of another chord CD from O is 4cm

To Find:

The length of chord CD

Solution:

Using the Pythagoras theorem we find the height of the triangle

(height)² = (base)² + (perpendicular)²

h² = b² + p²

Now, we substitute the values to find h

h² = (4)² + (6/2)²

h² = (4)² + (3)²

h² = 16 + 9

h² = 25

h = √25

h = 5

So, the height of the triangle is 5cm.

Now, again by using the Pythagoras theorem, we find the radius

r² = b² + p²

Then we substitute the following values

r² = (4)² + (CD/2)²

r² = (4)² + (CD)²/4

(6)² = (4)² + (CD)²/4

36-16 = (CD)²/4

20 = (CD)²/4

20/4 = (CD)²

5 = CD²

CD = √5

CD = 2.23

Therefore, the length of CD = √5

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