in a circle chord xyll chord kL also chord xy ~= chord kL .if chord kL is at a distance of 4.2 cm then find the distance between two chords
Answers
Given : xy || kL
xy ≅ kL
chord kL is at a distance of 4.2 cm
To Find: the distance between two chords
Solution:
chord kL is at a distance of 4.2 cm
Let say OM ⊥ kL
then OM = 4.2 cm perpendicular form center on chord bisect it
OM² = radius² - (kL/2)²
4.2² = radius² - (kL/2)²
Draw ON ⊥ xy
ON² = radius² - (xy/2)²
xy = kL
=> xy/2 = kL/2
=> ON² = 4.2²
=> ON = ±4.2
Distance between chords = OM + ON
= 4.2 ± 4.2
= 8.4 cm or 0 cm
0 cm means xy & kL are same chord
hence 8.4 cm is the distance between two chords
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