Question

in a circle if angle abc equal to 110 degree find angle ACB​

Answer 1

Answer:

Given,

angle at centre ∠AOB=110

angle at circumference ∠ACO

Now,

we know that the angle at the centre is twice the angle at the circumference subtended by the same arc.

Therefore,

∠AOB=2∠ACO

⟹110 =2∠ACO

⟹∠ACO= 110/2

=55

Now,

∠COA+∠AOB=180

⟹∠COA=180−110

=70

In△AOC,

∠AOC+∠ACO+∠CAO=180

⟹70 +55 +∠CAO=180

⟹∠CAO=55