In a circle is inscribed a quadrilateral ABCD in which B=90degree. If AD=23cm, AB=29cm and DS=5cm, find the radius of the incircle.
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Given : ABCD is a quadrilateral in which, AD = 23 cm, DS = 5 cm and AB = 29 cm
Let radius of the incircle be r cm.

And,

Now, OP and OQ are radius of the circle. So,
From tangents P and Q,

Hence, radius of the circle is 11 cm.
Let radius of the incircle be r cm.

And,

Now, OP and OQ are radius of the circle. So,
From tangents P and Q,

Hence, radius of the circle is 11 cm.
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