in a circle o the measure of minor Arc is 145 degree what is the measure of the major pyq ?
Answers
Answer:
Solution. Suppose PQ is the minor arc and then m(arc PQ) = 110°. We know that, measure of major arc = 360° − measure of corresponding minor arc. Hence, the measure of major arc PYQ is 250°.
Step-by-step explanation:
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Answer:
288
288 o
288 o
288 o Let minor arc = x
288 o Let minor arc = x o
288 o Let minor arc = x o
288 o Let minor arc = x o ⇒ major arc = (360 -x)
288 o Let minor arc = x o ⇒ major arc = (360 -x) o
288 o Let minor arc = x o ⇒ major arc = (360 -x) o
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x)
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o =360
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o =360 o
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o =360 o
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o =360 o ⇒x=
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o =360 o ⇒x= 5
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o =360 o ⇒x= 5360
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o =360 o ⇒x= 5360
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o =360 o ⇒x= 5360 =72
288 o Let minor arc = x o ⇒ major arc = (360 -x) o Given : major arc = 4 × minor arc ∴(360−x) o =4x o ⇒5x o =360 o ⇒x= 5360 =72 o
Step-by-step explanation:
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