in a circle of a centre 'p' chord AB=chord CD. if chord AB is at a distance of 2.8 cm from the centre of the circle then find the distance of chord CD from centre of the circle.
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Answer:
Let AB =8 cm. be the chord of the circle with radius AO=5 cm.
Draw OP⊥AB.join OA
according to the theorem
AP=
2
1
AB=
2
1
×8=4cm.
In △APO,∠A=90
∘
∴(AO)
2
=(AP)
2
+(OP)
2
OP=
(AO)
2
−(AP)
2
⇒
5
2
−4
2
⇒
9
⇒OP=3cm
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