in a circle of centre O,TP and TQ are the tangents ,so that angle POQ=110°.Then find angle PTQ.
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Answered by
14
angle PTQ =70°
is the answer bro.
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Answered by
20
Ans - we know that two tangent drawn from an external point of a circle is supplementary to the angle subtended by the line segment joining the point of contact at the center.
POQ angle plus PTQ angle = 180 degree
As we know that POQ angle =110 degree.
So PTQ = 180 - 110 = 70 degree.
Step-by-step explanation:
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