Question

In a circle of diameter 40 cm, the length
of a chord is 20 cm. Find the length of
minor arc of the chord.
(11th std question)​

Answer 1

Step-by-step explanation:

diameter is 40 cm

radius is 20 cm

AB is 20 cm

AC is 20 cm

BC is length of chord 20 cm

so, AB=AC=BC=20 cm

hence ∆ABC is an equateral

Answer 2

Answer:

radius=4o/2 = 20 cm

length of the chord=20cm

Central angle=60°(as the triangle formed is an equilateral triangle each angle 60° and sides are 20cm each

Length of. minor Arc=x/360X2πr

= 60.x2x22x20/360x7=20.95cm