Question

In a circle of diameter 40 cm the length of a chord is 20 cm find the length of minor arc of the chord

Answer 1

Step-by-step explanation:

Diameter of the circle =40 cm

∴ Radius (r) of the circle =

2

40

=20 cm

Let AB be a chord (length = 20 cm) of the circle.

In △OAB, OA = OB = Radius of circle = 20 cm

Also, AB = 20 cm

Thus, △OAB is an equilateral triangle.

∴θ=60

∘

=

3

π

radian

We know that in a circle of radius r unit, if an arc of length I unit subtends an angle θ radian at the centre, then θ=

r

l

∴

3

π

=

20

arc AB

⟹arc AB=

3

20

π cm

hope it helps plzz mark as brainliest

Answer 2

Answer:

Step-by-step explanation:

in question given

diameter = 40 cm

radius = D/2

= 40/2

= 20cm.

the length of a chord is 20cm.

a/q

∆ OAB is equilateral traingle.

θ = 60°

l = 20 × 60° × π / 180°

l = 20π / 3cm

thus,

the length of the minor arc of the chord

20π / 3cm