In a circle of diameter 40 cm the length of a chord is 20cm. Find the о length of minor arc of the chord.
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In triangle AOB, OA = OB = 20 cm (radii of the circle)
AB = 20 cm (given the length of the chord)
∴ Triangle AOB is an equilateral triangle with all sides equal.
⇒ Θ = 60° = π / 3 radian.
As we know that, in a circle of radius r unit, if the length of the arc is l unit subtends at an angle Θ radian at the center, then l = r × Θ
⇒ l = 20 × π / 3
⇒ l = 20 π/3 cm
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