Question

in a circle of diameter 40 cm , the length of a chord is 20cm. find the length of the minor arc of the chord ?

Answer 1

Given:

Diameter=40cm

Length of the chord=20cm

Radius=20cm

Since radius=length of chord=20cm

Hence the formed ΔΔle in the circle is equilateral ΔΔle

⇒θ=60∘⇒θ=60∘

We know that l=rθl=rθ

l=20×60∘×π180∘l=20×60∘×π180∘

l=20π3l=20π3

Thus length of the minor arc of the chord is 20π3

Answer 2

in question given

diameter = 40 cm

radius = D/2

= 40/2

= 20cm.

the length of a chord is 20cm.

a/q

∆ OAB is equilateral traingle.

θ = 60°

l = 20 × 60° × π / 180°

l = 20π / 3cm

thus,

the length of the minor arc of the chord
20π / 3cm

be brainly