In a circle of diameter 40cm, the length of a chord is 20cm.find the length of minor arc of the chord.
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Answer:
di. of the circle = 40 cm
then rad. = 20 cm
now chord = 20cm
the triangle formed is an equilateral triangle with each side = 20cm
Θ = 60°
now length of the arc is I = rΘ
= 20(60°*п(pi) /180°)
= 20π/3cm
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