Question

In a circle of diameter 40cm, the length of a chord is 20cm. Find the length of minor are of the chord.​

Answer 1

Answer:

Given that in a circle of diameter 40 cm, the length of a chord is 20 cm. The length of minor arc of the chord is 20 π/3 cm.

Answer 2

Diameter of the circle =40 cm

∴ Radius (r) of the circle =20 cm

Let AB be a chord (length = 20 cm) of the circle.

In △OAB, OA = OB = Radius of circle = 20 cm

Also, AB = 20 cm

Thus, △OAB is an equilateral triangle.

∴θ=60 ∘ = π/3 radian

We know that in a circle of radius r unit, if an arc of length I unit subtends an angle θ radian at the centre, then θ= l/r

​∴ π/3= (arc AB)/20

​⟹arc AB= 20π/3 cm