In a circle of diameter 42cm,if an arc subtends an angle of 60˚ at the centre
where ∏=22/7, then what will be the length of arc.
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r = 21 cm.
theta = 60°
pii = 22/7.
ans :-
as we know that
L = r × theta
where theta should be in radian.
therefore L= r× theta
L = 21 × 60 × pii/ 180
L = 21/3 × pii
L = 21/3 × 22/7
L = 22 cm
therefore thought of arc is 22 cm
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Given: a circle of diameter 42 cm
arc subtends an angle of 60˚ at the center
π = 22/7
To Find :length of arc.
Solution:
Radius = Diameter/2
=> Radius r = 42/2 = 21 cm
Length of arc = ( arc angle/360°) 2πr
= ( 60°/360°) 2(22/7) 21
= (1/6) (2) (22) 3
= 22
Length of arc = 22 cm
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